Given that , find .
Find the smallest positive integer such that .
Find the largest negative integer such that .
Find the highest common factor and the lowest common multiple of and , and write the highest common factor as an integral linear combination of and .
For each of the following three congruences, determine whether or not it has solutions; if solutions exist, find the complete solution:
Given that , explain why the pair of congruences
have no simultaneous solutions.
Show that the numbers and are coprime, and write as an integral linear combination of them.
Use the Chinese Remainder Theorem to find the complete solution to the pair of congruences
that is, find all integers which satisfy the two congruences simultaneously.
State the prime factorizations of and .
Find the highest common factor and the lowest common multiple of and .
Determine how many positive factors and have.
A certain private school has fewer than pupils. They are allocated into teams of eight for rowing and eleven for hockey. Six are left over and get out of rowing; similarly four get out of hockey. How many pupils are there?
Suppose that the Sieve of Eratosthenes is applied to find all primes up to ; so firstly multiples of are crossed out, secondly multiples of , thirdly multiples of and so on. How many times would it be necessary to go through the grid crossing out multiples in this way?
For each of the following four congruences, determine whether or not it has solutions; if solutions exist, find the complete solution.
(i) | ; | (ii) | ; | |
(iii) | ; | (iv) | . |
Use the Chinese Remainder Theorem to find the complete solution to the pair of congruences and .
Prove that there are infinitely many primes of the form .
[Hint: mimic the proof of Theorem 4.7.1; suppose that
are the only primes of this form, and consider
.]
The answers to the following exercises must be handed in in your tutor’s pigeonhole (B Floor, Fylde College) no later than 17.00, Wednesday November.
(6 points) For each of the following two congruences, decide whether it has solutions; if solutions exist, find the complete solution:
(4 points) The first-year maths students at a certain university are divided into workshop groups of each and computer lab groups of each. One group is always filled up completely before a new group is created. One year, the final workshop group has students in it, while the final computer lab group consists of students only. It is known that less than first-year students study mathematics. How many such students are there exactly?
The answers to the exercises below must be submitted online no later than 23.59, Wednesday November.
(Prime factorization) Find the prime factorizations of and , and hence determine: (i) the highest common factor of and ; (ii) the lowest common multiple of and ; and (iii) the number of positive factors of . Then decide which one of the following five statements is true:
, and ;
, and ;
, and ;
, and ;
, and .
(Existence of solutions to congruences) Decide which one of the following five statements is true:
all three congruences
have solutions;
none of the three congruences above have solutions;
the congruences and both have solutions, but the congruence does not;
the congruences and both have solutions, but the congruence does not;
the congruence has solutions, but the congruences and do not.
(The complete solution to a congruence) Decide which one of the following five statements about the congruence is true:
no solutions exist;
the complete solution is given by
the complete solution is given by
the complete solution is given by
the complete solution is given by
(Solving a pair of congruences I) For the pair of congruences
decide which one of the following five statements is true:
no simultaneous solutions exist;
the complete solution is given by
the complete solution is given by
the complete solution is given by
none of the above.
(Solving a pair of congruences II) For the pair of congruences
decide which one of the following five statements is true:
no simultaneous solutions exist;
the complete solution is given by
the complete solution is given by
the complete solution is given by
none of the above.
These exercises are harder than the tutor-assessed exercises above and are not compulsory; however, if you solve either or both of them, then any points gained here will be added to your score in this week’s tutor-assessed exercises, up to a maximum total score of points.
(3 points)
For , show that if
, then .
[Hint: prime factorization.]
For each , prove that either or .
(3 points) Decide whether simultaneous solutions exist to the pair of congruences
If they do, find the complete solution.