Let . For each of the following four values of , find such that and (as in Theorem 4.1.8):
(i) | ; | (ii) | ; | |
(iii) | ; | (iv) | . |
Use the Euclidean algorithm to find the highest common factor of and , and express it as an integral linear combination of and .
For each of the two numbers and , either write it as an integral linear combination of and or explain why this is impossible, using Proposition 4.4.2.
Prove the following two statements about integers and :
if and are both even, then is even;
if is even, then at least one of and is even. [Hint: contraposition.]
Let , and be non-zero integers. Prove that if is a factor of , then is also a factor of . [Hint: use Theorem 4.2.17.]
Show that, for each real number , at least one of and is irrational. [Hint: proof by contradiction — what would follow if both were rational? Recall from Example 3.4.2 that is irrational.]
Find the sets of factors of and .
Using (i), determine the set of common factors of and , and hence find their highest common factor.
For each of the numbers , , and , decide whether or not it can be written as an integral linear combination of and .
Use the Euclidean algorithm to find the highest common factor of and , and express it as an integral linear combination of and .
For integers and , prove that the integer is always even. [Hint: consider cases separately.]
Show that one of the following two statements is true, whereas the other is false:
Let , and be non-zero integers, and suppose that and are coprime and that and are coprime. Show that and are coprime. [Hint: use Corollary 4.2.19.]
Let , and be non-zero integers. Prove that if and are coprime and is a factor of , then and are coprime. [Hint: use Corollary 4.2.19.]
List the sets of factors of and , and hence find the set of their common factors and their highest common factor.
For integers and , prove that the integer is even if and only if and are both even.
The answers to the following two exercises must be handed in in your tutor’s pigeonhole (B Floor, Fylde College) no later than 17.00, Wednesday October.
(6 points) For each of the following two statements, decide whether it is true or false, and justify your answer by giving a proof or a counterexample, as appropriate:
.
(4 points) For non-zero integers , and , prove that if is a factor of , then is also a factor of . [Hint: use Theorem 4.2.17.]
The answers to the exercises below must be submitted online no later than 23.59, Wednesday October.
(Division with remainder) Let . For , find such that with (as in Theorem 4.1.8). Moreover, for , find such that with . Then choose the correct answer from the following list:
and ; and ;
and ; and ;
and ; and ;
and ; and ;
none of the above.
Use the Euclidean algorithm to find the highest common factor of and , and then reverse the steps of the algorithm to find integers and such that . Then answer the following two questions.
(The highest common factor ) The value of is:
none of the above.
(The integers and ) The values of and found by this method are:
and
and
and
and
none of the above.
(Integral linear combinations and the highest common factor) Find the highest common factor of and , and then decide which one of the following five statements is true:
each of the numbers , and can be written as an integral linear combination of and ;
none of the numbers , and can be written as an integral linear combination of and ;
the number can be written as an integral linear combination of and , whereas and cannot be written as integral linear combinations of and ;
the number can be written as an integral linear combination of and , whereas and cannot be written as integral linear combinations of and ;
the number can be written as an integral linear combination of and , whereas and cannot be written as integral linear combinations of and .
(Correctness of a proof) Four students, Alice, Bob, Claire and Dave, have each attempted to prove that the following statement is false.
‘‘Let be a multiple of , and let be a multiple of . Then is an integral linear combination of and , but is not an integral linear combination of and .’’
Their answers are as follows:
We have and . Since , the statement is false.
The statement is false because , which divides both and , so both numbers are integral linear combinations of and by Proposition 4.4.2.
The statement is false because is a multiple of , and is a multiple of , but since , we cannot write as an integral linear combination of and .
We begin by negating the statement:
‘‘There exist which is not a multiple of and which is not
a multiple of such that is not an integral linear combination
of and , but is an integral linear combination of and .’’
To prove that this is true, we choose , which is not a multiple of , and , which is not a multiple of . Then , which divides , but not , so Proposition 4.4.2 shows that is an integral linear combination of and , but is not. This shows that the negation is true, so the original statement is false.
Decide which one of the following five statements about these answers is true:
only one student gave a correct answer;
Alice’s and Bob’s solutions are the only correct ones;
Claire’s and Dave’s solutions are the only correct ones;
only one student gave an incorrect answer;
none of the above.
This exercise is harder than the tutor-assessed exercises above and is not compulsory; however, if you solve it, then any points gained here will be added to your score in this week’s tutor-assessed exercises up to a maximum total score of points.
(3 points) Let and be non-zero integers. Prove that if and are coprime, then and are also coprime. [Hint: Exercise 2.12 may be helpful.]