Explain why the number cannot be written as the sum of two squares.
Find (i) and (ii) without actually calculating or (or any other numbers greater than ).
For each of the following two relations, decide if it is
(a) reflexive,
(b) symmetric and (c) transitive:
, and if ;
, and if .
In each case give a proof or a counterexample as appropriate.
Show that divides for each .
In the construction of from given in Section 6.4 of the lecture notes, show that for all , and (where with ) we have
(This rule is called the distributive law.)
On the set , define a relation by stipulating that if (where ). For each , let .
Find the set explicitly for each element .
Do the sets form a partition of ?
Is an equivalence relation?
Give the addition and multiplication tables in . From the second of these, decide if the equation has a solution in , and justify your answer.
Let , and let . We say that is a zero divisor in if for some .
Use the multiplication table found in Exercise 4.8 to find the zero divisors in .
Use the similar table in the notes to find the zero divisors in .
Define a relation on the set by
Show that is an equivalence relation.
What is wrong with the following argument to show that any relation which is both symmetric and transitive must also be reflexive?
From we deduce that as is symmetric, and then we have as is transitive — so is reflexive.
[Hint: it may help to consider one of the relations in Exercise 4.3 above.]
Show that no number ending in , , or can be a perfect square.
Find the remainder on dividing by without actually calculating (or any other numbers greater than ).
Show that divides for each .
[Hint: begin by considering and modulo .]
The answers to the following exercises must be handed in in your tutor’s pigeonhole (B Floor, Fylde College) no later than 17.00, Wednesday November.
(5 points) On the set , define a relation by stipulating that if (where ). Decide whether this relation is (a) reflexive, (b) symmetric and (c) transitive, in each case giving either a proof or a counterexample, as appropriate.
(1 point) Explain why the number cannot be written as the sum of two squares, giving clear reference to any results that you use.
(4 points) Show that divides for each .
The answers to the exercises below must be submitted online no later than 23.59, Wednesday November.
(A relation) On the set of all real functions, define a relation by stipulating that if (where and are real functions). Decide which one of the following five statements is true:
the relation is reflexive, but not symmetric or transitive;
the relation is reflexive and symmetric, but not transitive;
the relation is reflexive and transitive, but not symmetric;
the relation is symmetric, but not reflexive or transitive;
none of the above.
(The remainder on dividing by ) Find the remainder on dividing by without actually calculating (or any other numbers greater than ), and then decide which one of the following five statements is true:
none of the above.
(The remainder on dividing by ) Find the remainder on dividing by without actually calculating (or any other numbers greater than ), and then decide which one of the following five statements is true:
none of the above.
(Polynomial division) Suppose that we divide a polynomial of degree by a polynomial of degree using polynomial division with remainder (Theorem 7.1.10) to obtain a quotient and a remainder . Suppose further that , and then decide which one of the following five statements is true:
has degree , and has degree at most ;
has degree , and may have degree ;
has degree , and has degree at most ;
has degree , and may have degree ;
none of the above.
(A polynomial relation) Ann, Bill, Chris, Dan and Ed use the exam paper from 2015 to revise for the MATH111 end-of-module test. However, they cannot agree on the correct answer to Question 4(a), which reads as follows:
Let denote the set of real polynomials, and let , so that is the set of non-zero real polynomials. Define a relation on by stipulating that
(where are polynomials and ). Decide whether
and whether
Ann says that both statements hold, Bill that only the first one holds, Chris that only the second one holds, Dan that neither holds, and Ed that the question does not make sense — there must be a typo in the exam paper because we do not have enough information to answer the question. Who is right?
(A) Ann, (B) Bill, (C) Chris, (D) Dan, (E) Ed.
This exercise is harder than the tutor-assessed exercises above and is not compulsory; however, if you solve it, then any points gained here will be added to your score in this week’s tutor-assessed exercises, up to a maximum total score of points.
(3 points) Let , and let . Recall from Exercise 4.10 that is a zero divisor in if for some . Prove that is a zero divisor in if and only if .