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1.13 General remarks

Although we didn’t prove this, it is true that if degree⁢f<degree⁢g\hbox{degree}\,f<\hbox{degree}\,g then the polynomial term is zero. Hence the first step is always to divide f⁢(x)f(x) by g⁢(x)g(x) as in frame 1.3, separating off the polynomial term. The rational function which remains will then be a sum of terms of the form γ(x-a)r\frac{\gamma}{(x-a)^{r}} and α+β⁢xQ⁢(x)r\frac{\alpha+\beta x}{Q(x)^{r}}.

Warning 1: When g⁢(x)g(x) has an irreducible quadratic factor, it is not enough to consider expressions of the form BQ⁢(x)r\frac{B}{Q(x)^{r}} with BB a constant.

Warning 2: When g⁢(x)g(x) has an irreducible quadratic factor or a squared linear factor, the usual shortcut for finding the coefficients via ‘evaluating at roots’ is not available.