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1.13 General remarks

Although we didn’t prove this, it is true that if degreef<degreeg\hbox{degree}\,f<\hbox{degree}\,g then the polynomial term is zero. Hence the first step is always to divide f(x)f(x) by g(x)g(x) as in frame 1.3, separating off the polynomial term. The rational function which remains will then be a sum of terms of the form γ(x-a)r\frac{\gamma}{(x-a)^{r}} and α+βxQ(x)r\frac{\alpha+\beta x}{Q(x)^{r}}.

Warning 1: When g(x)g(x) has an irreducible quadratic factor, it is not enough to consider expressions of the form BQ(x)r\frac{B}{Q(x)^{r}} with BB a constant.

Warning 2: When g(x)g(x) has an irreducible quadratic factor or a squared linear factor, the usual shortcut for finding the coefficients via ‘evaluating at roots’ is not available.