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3.5 Length of a curve

We think of d⁢s2=d⁢x2+d⁢y2ds^{2}=dx^{2}+dy^{2} and write L=∫d⁢s.L=\int ds. Let PP and QQ be points on a curve CC that has parametric form (x⁢(t),y⁢(t))(x(t),y(t)), so that P=(x⁢(a),y⁢(a))P=(x(a),y(a)) and Q=(x⁢(b),y⁢(b))Q=(x(b),y(b)).

Then the length of the curve from PP to QQ is

L=∫ab(d⁢xd⁢t)2+(d⁢yd⁢t)2⁢d⁢t.L=\int_{a}^{b}\sqrt{\Bigl({{dx}\over{dt}}\Bigr)^{2}+\Bigl({{dy}\over{dt}}\Bigr% )^{2}}\,dt.

We write

s⁢(t)=∫at(d⁢xd⁢u)2+(d⁢yd⁢u)2⁢d⁢us(t)=\int_{a}^{t}\sqrt{\Bigl({{dx}\over{du}}\Bigr)^{2}+\Bigl({{dy}\over{du}}% \Bigr)^{2}}\,du

for the arclength from PP to the point (x⁢(t),y⁢(t))(x(t),y(t)), so

(d⁢sd⁢t)2=(d⁢xd⁢t)2+(d⁢yd⁢t)2.\Bigl({{ds}\over{dt}}\Bigr)^{2}=\Bigl({{dx}\over{dt}}\Bigr)^{2}+\Bigl({{dy}% \over{dt}}\Bigr)^{2}.

The perimeter of a figure is the arclenth of the curve that goes once around the boundary.