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12.4 Answers to 2012 test

2. For the partial fractions, we have 5⁢x+4(x+3)⁢(x2+2)=x+2x2+2-1x+3\frac{5x+4}{(x+3)(x^{2}+2)}=\frac{x+2}{x^{2}+2}-\frac{1}{x+3}. For the indefinite integral, we have

∫5⁢x+4(x+3)⁢(x2+2)⁢d⁢x=12⁢log⁡(x2+2(x+3)2)+2⁢tan-1⁡x2+c.\int\frac{5x+4}{(x+3)(x^{2}+2)}\,dx=\frac{1}{2}\log\left(\frac{x^{2}+2}{(x+3)^% {2}}\right)+\sqrt{2}\tan^{-1}\frac{x}{\sqrt{2}}+c.

The integral converges to π⁢22+12⁢log⁡92\frac{\pi\sqrt{2}}{2}+\frac{1}{2}\log\frac{9}{2}.

3. a) d⁢yd⁢x=sin⁡t+t⁢cos⁡tcos⁡t-t⁢sin⁡t\frac{dy}{dx}=\frac{\sin t+t\cos t}{\cos t-t\sin t}.

b) When t=0t=0, we have d⁢yd⁢x=01=0\frac{dy}{dx}=\frac{0}{1}=0 so the tangent line is parallel to the xx-axis.

c) The arc length is 12⁢sinh-1⁡π+12⁢π⁢1+π2=12⁢log⁡(π+1+π2)+12⁢π⁢1+π2\frac{1}{2}\sinh^{-1}\pi+\frac{1}{2}\pi\sqrt{1+\pi^{2}}=\frac{1}{2}\log(\pi+% \sqrt{1+\pi^{2}})+\frac{1}{2}\pi\sqrt{1+\pi^{2}}.

4. a) False, since the region of integration a≤y≤ba\leq y\leq b, c≤x≤dc\leq x\leq d is different to the region of integration a≤x≤ba\leq x\leq b, c≤y≤dc\leq y\leq d.

b) True, since the Hessian discriminant Δ=-3\Delta=-3 is always negative.

c) False: the gradient is -fxfy-\frac{f_{x}}{f_{y}}.

5. The value of the integral is 536\frac{53}{6}.