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12.3 Answers to 2013 test

2. a) The Laplace transform of x2exx^{2}e^{x} is 2(s-1)3\frac{2}{(s-1)^{3}}, and it converges for s>1s>1.

b) i) f(R)f(R) diverges as RR\rightarrow\infty.

ii) g(δ)log12=-log2g(\delta)\rightarrow\log\frac{1}{2}=-\log 2 as δ\delta tends to 00 from above.

3. i) False: the gradient (by implicit differentiation) is 6x-23y2\frac{6x-2}{3y^{2}}, which equals 56\frac{5}{6} at (2,2)(2,2).

ii) False, e.g. f(x,y)=x+yf(x,y)=x+y has no stationary points, but fx=fyf_{x}=f_{y} everywhere.

iii) True: the Hessian discriminant Δ=fxxfyy-fxy2fxxfyy<0\Delta=f_{xx}f_{yy}-f_{xy}^{2}\leq f_{xx}f_{yy}<0, so every stationary point is a saddle.

4. a) We obtain the estimate: 0π21-59sin2tdtπ12(53+41318)1.33\int_{0}^{\frac{\pi}{2}}\sqrt{1-\frac{5}{9}\sin^{2}t}\,dt\approx\frac{\pi}{12}% (\frac{5}{3}+4\sqrt{\frac{13}{18}})\approx 1.33.

b) Using the parametrization and the arc-length formula we obtain that the perimeter of the ellipse is 120π21-59sin2tdt15.912\int_{0}^{\frac{\pi}{2}}\sqrt{1-\frac{5}{9}\sin^{2}t}\,dt\approx 15.9.