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1.27 Reducing tan⁡x2\tan\frac{x}{2}

Secondly,

sin⁡x=2⁢sin⁡x2⁢cos⁡x2=2⁢tan⁡x2⁢cos2⁡x2\sin x=2\sin\frac{x}{2}\cos\frac{x}{2}={2\tan\frac{x}{2}\cos^{2}\frac{x}{2}}
=2⁢tan⁡x2sec2⁡x2=2⁢t1+t2{=\frac{2\tan\frac{x}{2}}{\sec^{2}\frac{x}{2}}=\frac{2t}{1+t^{2}}}

and

cos⁡x=2⁢cos2⁡x2-1=2sec2⁡x2-1\cos x={2\cos^{2}\frac{x}{2}-1=\frac{2}{\sec^{2}\frac{x}{2}}-1}
=21+t2-1=2-1-t21+t2=1-t21+t2.{=\frac{2}{1+t^{2}}-1=\frac{2-1-t^{2}}{1+t^{2}}=\frac{1-t^{2}}{1+t^{2}}.}