Home page for accesible maths Math 101 Venue for MATH101 Calculus Test 2016

Style control - access keys in brackets

Font (2 3) - + Letter spacing (4 5) - + Word spacing (6 7) - + Line spacing (8 9) - +

Question 2

2. (i) Show that

113+124++1N(N+2)=12(1+12-1N+1-1N+2),{{1}\over{1\cdot 3}}+{{1}\over{2\cdot 4}}+\dots+{{1}\over{N\cdot(N+2)}}={{1}% \over{2}}\Bigl(1+{{1}\over{2}}-{{1}\over{N+1}}-{{1}\over{N+2}}\Bigr),

where aba\cdot b denotes the product of aa and bb.

(ii) Deduce the value of the sum of the series

113+124+.{{1}\over{1\cdot 3}}+{{1}\over{2\cdot 4}}+\dots.

[6]