MATH319 Slides

86 Example

Example

To solve the integral equation

y⁢(t)=2⁢ea⁢t+∫0teb⁢(t-u)⁢y⁢(u)⁢𝑑u

where a,b are constants with a≠b+1, and y satisfies (E). Solution. Note that the the integral is a convolution of y with eb⁢t, so by Proposition 73(iii), we have

y^⁢(s)=2s-a+y^⁢(s)s-b;

after a little reduction we obtain

y^⁢(s)=2⁢(s-b)(s-a)⁢(s-b-1);