MATH319 Slides

48 Solving the basic linear differential equation

Theorem

Suppose that A is a constant (n×n) matrix and that U⁢(t) is a (n×k) matrix with continuous functions [0,∞)→𝐂 as entries. Then for any constant (n×k) complex matrix X0, the (n×k) matrix function

X⁢(t)=exp⁡(t⁢A)⁢X0+∫0texp⁡((t-s)⁢A)⁢U⁢(s)⁢𝑑s

satisfies the matrix differential equation

d⁢Xd⁢t=A⁢X+U

with initial value

X⁢(0)=X0.