MATH319 Slides

164 Proof

Suppose that K=X/Y. Then, as in frame 161,

I+G⁢K=1+XY⁢PQ=Y⁢Q+X⁢PY⁢Q=1Y⁢Q;

so 11+G⁢K=Y⁢Q and hence Φ has all entries in 𝒮, since

Φ=Y⁢Q⁢[1-P/Q-1X/Y1-X/YP⁢X/Y⁢QP/Q1]=[Y⁢Q-Y⁢P-Y⁢QX⁢QY⁢Q-X⁢QX⁢PY⁢PY⁢Q].