MATH319 Slides

130 A solution of Lyapunov’s equation

Corollary

Suppose that A is a real square matrix such all its eigenvalues are in the open left half plane {λ∈𝐂:ℜ⁡λ<0}. Then for all positive definite P, there exists a positive definite K such that

A⁢K+K⁢A†=-P.

Note that exp⁡(t⁢A)⁢P⁢exp⁡(t⁢A†) is positive definite by exercise A3.2. Indeed ⟨exp⁡(t⁢A)⁢P⁢exp⁡(t⁢A†)⁢Y,Y⟩=⟨P⁢exp⁡(t⁢A†)⁢Y,exp⁡(t⁢A†)⁢Y⟩ is positive and continuous for t>0 and Y≠0. Hence

K=∫0∞exp⁡(t⁢A)⁢P⁢exp⁡(t⁢A†)⁢𝑑t

is also positive definite. [MATLAB gives K=l⁢y⁢a⁢p⁢(A,P).]