MATH319 Slides

129 Solution of Sylvester’s equation

(i) First observe that by Lemma 118 there exist M1,M2,δ1,δ2>0 such that exp(tA)M1e-δ1t and exp(tB)M2e-δ2t, so the integral is convergent. Also

AY+YB=0(Aexp(tA)Cexp(tB)+exp(tA)Cexp(tB)B)𝑑t
AY+YB=0ddt(exp(tA)Cexp(tB))𝑑t
=[exp(tA)Cexp(tB)]0=-C.

Uniqueness follows from the Proposition 127 since A and -B have no common eigenvalues.