MATH319 Slides

129 Solution of Sylvester’s equation

(i) First observe that by Lemma 118 there exist M1,M2,δ1,δ2>0 such that ∥exp⁡(t⁢A)∥≤M1⁢e-δ1⁢t and ∥exp⁡(t⁢B)∥≤M2⁢e-δ2⁢t, so the integral is convergent. Also

A⁢Y+Y⁢B=∫0∞(A⁢exp⁡(t⁢A)⁢C⁢exp⁡(t⁢B)+exp⁡(t⁢A)⁢C⁢exp⁡(t⁢B)⁢B)⁢𝑑t
A⁢Y+Y⁢B=∫0∞dd⁢t⁢(exp⁡(t⁢A)⁢C⁢exp⁡(t⁢B))⁢𝑑t
=[exp⁡(t⁢A)⁢C⁢exp⁡(t⁢B)]0∞=-C.

Uniqueness follows from the Proposition 127 since A and -B have no common eigenvalues.