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C.5 Practice Proof 2

Here’s another more complicated proof for practice. This time, a definition is provided too. Remember: use the self-explanation training after every line you read, either in your head or by writing on paper.

Definition. An abundant number is a positive integer nn whose divisors add up to more than 2n2n. For example, 1212 is abundant because 1+2+3+4+6+12>241+2+3+4+6+12>24.

Theorem.The product of two distinct primes is not abundant.

Proof. Let n=p1p2n=p_{1}p_{2}, where p1p_{1} and p2p_{2} are distinct primes.

Assume that 2p12\leqslant p_{1} and 3p23\leqslant p_{2}.

The divisors of nn are 1,p1,p21,p_{1},p_{2} and p1p2p_{1}p_{2}.

Note that p1+1p1-1\displaystyle\frac{p_{1}+1}{p_{1}-1} is a decreasing function of p1p_{1}.

So max{p1+1p1-1}=2+12-1=3\displaystyle\max\left\{\frac{p_{1}+1}{p_{1}-1}\right\}=\frac{2+1}{2-1}=3.

Hence p1+1p1-1p2\displaystyle\frac{p_{1}+1}{p_{1}-1}\leqslant p_{2}.

So p1+1p1p2-p2p_{1}+1\leqslant p_{1}p_{2}-p_{2}.

So p1+1+p2p1p2p_{1}+1+p_{2}\leqslant p_{1}p_{2}.

So 1+p1+p2+p1p22p1p21+p_{1}+p_{2}+p_{1}p_{2}\leqslant 2p_{1}p_{2}. \square