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C.4 Practice Proof 1

Now read this short theorem and proof and self-explain each line, either in your head or by making notes on a piece of paper, using the advice from the preceding pages.

Theorem.There is no smallest positive real number.

Proof. Assume, to the contrary, that there exists a smallest positive real number.

Therefore, by assumption, there exists a real number rr such that for every positive number ss, 0<r<s0<r<s.

Consider m=r2m=\frac{r}{2}.

Clearly, 0<m<r0<m<r.

This is a contradiction because mm is a positive real number that is smaller than rr.

Thus there is no smallest positive real number. \square