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3.19 Basic examples of the Chain Rule

Example.

3.19.1 (Straight lines). Let (x⁢(t),y⁢(t))=(a+t⁢h,b+t⁢k)(x(t),y(t))=(a+th,b+tk). Then (x⁢(t),y⁢(t))(x(t),y(t)) describes a straight line segment as tt varies. For any function f⁢(x,y)f(x,y) we have

d⁢fd⁢t=∂⁡f∂⁡x⁢h+∂⁡f∂⁡y⁢k.{{df}\over{dt}}={{\partial f}\over{\partial x}}h+{{\partial f}\over{\partial y% }}k.
Example.

3.19.2 (Circle).Let x⁢(t)=cos⁡tx(t)=\cos t and y⁢(t)=sin⁡ty(t)=\sin t. Determine d⁢fd⁢t\frac{df}{dt}.

Solution. We have d⁢xd⁢t=-sin⁡t⁢and⁢d⁢yd⁢t=cos⁡t.\frac{dx}{dt}=\,{-\sin t}\;\mbox{and}\;\frac{dy}{dt}=\,{\cos t.}

So d⁢fd⁢t=-sin⁡t⁢∂⁡f∂⁡x+cos⁡t⁢∂⁡f∂⁡y=-y⁢fx+x⁢fy.\frac{df}{dt}=\,{-\sin t\frac{\partial f}{\partial x}+\cos t\frac{\partial f}{% \partial y}}\,{=-yf_{x}+xf_{y}.}