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3.16 Change in a function along a curve

We wish to analyze how f⁢(x,y)f(x,y) changes as we move from (x,y)(x,y) to a nearby point (x+h,y+k)(x+h,y+k) in the plane. There are many possible routes, and we consider here movements parallel to the co–ordinates axes. We move horizontally from (x,y)(x,y) to (x+h,y)(x+h,y) and then move vertically from (x+h,y)(x+h,y) to (x+h,y+k)(x+h,y+k). Then the change in f⁢(x,y)f(x,y) is: \curve(10,65,15,55) \curve(10,65,5,55) \curve(150,10,140,15) \curve(150,10,140,5) \curve(40,25,50,30,70,50,75,55) f⁢(x,y)f(x,y)f⁢(x+h,y)f(x+h,y)f⁢(x+h,y+k)f(x+h,y+k)f⁢(x+h,y+k)-f⁢(x,y)=f(x+h,y+k)-f(x,y)=(f⁢(x+h,y+k)-f⁢(x+h,y))(f(x+h,y+k)-f(x+h,y))+(f⁢(x+h,y)-f⁢(x,y))+(f(x+h,y)-f(x,y))≈k⁢∂⁡f∂⁡y+h⁢∂⁡f∂⁡x\approx k\frac{\partial f}{\partial y}+h\frac{\partial f}{\partial x}.

Hence all the subsequent chain rules will involve partial derivatives in the xx and yy directions. As we move along the curve CC with parametric form (x⁢(t),y⁢(t))(x(t),y(t)), then f⁢(x⁢(t),y⁢(t))f(x(t),y(t)) is a function of tt.