The integral ∫01dxx(1+x2)\int_{0}^{1}{{dx}\over{x(1+x^{2})}} diverges.
Solution. We simplify the integral using partial fractions:
where A(x2+1)+(Bx+C)x=1A(x^{2}+1)+(Bx+C)x=1, so that A=1A=1, B=-1B=-1 and C=0C=0. Thus
Since every term except logδ\log\delta converges as δ→0\delta\rightarrow 0, the integral diverges.