To determine the nature of the stationary point of the function
and sketch its graph.
Solution. We compute the derivative by the product rule
Now the stationary point occurs where f′(x)=0f^{\prime}(x)=0; that is, logx=-1\log x=-1, so x=1/ex=1/e, and f(1/e)=-1/ef(1/e)=-1/e and f′′(1/e)=e>0.f^{\prime\prime}(1/e)=e>0. Hence there is a local minimum at (1/e,-1/e).(1/e,-1/e).