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4.23 Limits of xlogxx\log x

4.23.1 Example

The following equivalent statements hold:

(i) eu/ue^{u}/u\rightarrow\infty as uu\rightarrow\infty;

(ii) ue-u0ue^{-u}\rightarrow 0 as uu\rightarrow\infty;

(iii) xlogx0x\log x\rightarrow 0 as x0+x\rightarrow 0+.

Solution. (i) For u>0u>0, we have

eu=1+u+u22!+u22,e^{u}=1+u+{{u^{2}}\over{2!}}+\dots\geq{{u^{2}}\over{2}},

so eu/uu/2e^{u}/u\geq u/2; hence eu/ue^{u}/u\rightarrow\infty as uu\rightarrow\infty.