MATH319 Slides

154 Example

Let

G(s)=s2+5s2-s+1.

Then with s=(1-λ)/λ, we have

G(s)=(1-λ)2+5λ2(1-λ)2-λ(1-λ)+λ2=6λ2-2λ+13λ2-3λ+1.

Then by the Euclidean algorithm

(24λ-27)(3λ2-3λ+1)-(12λ-97)(6λ2-2λ+1)=1

so letting λ=1/(1+s), we have PX+QY=1 with P,Q,X,Y𝒮

(22-2s7(1+s))(3(1+s)2-31+s+1)-(3-9s7(1+s))(6(1+s)2-21+s+1)=1.