Home page for accesible maths 5.7 Conditional Distributions

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5.8 Key definitions and Relationships

Let (X,Y) be a bivariate rv.

  1. 1.

    The joint cdf is FX,Y(x,y)=𝖯(Xx,Yy). FX(x)=FX,Y(x,).

  2. 2.

    For a discrete rv, the joint pmf is pX,Y(x,y)=𝖯(X=x,Y=y).

  3. 3.

    For a continuous rv, the joint pdf is fX,Y(x,y)=2xyFX,Y(x,y).

  4. 4.

    For discrete rvs X and Y, the marginal pmf of X, is pX(x)=j=-pX,Y(x,j), and the conditional pmf of X given Y=y is pX|Y(x|y)=pX,Y(x,y)/pY(y).

  5. 5.

    For continuous rvs X and Y, the marginal pdf of X is fX(x)=t=-fX,Y(x,t)dt, and the conditional pdf of X given Y=y is fX|Y(x|y)=fX,Y(x,y)/fY(y).

  6. 6.

    X and Y are independent if and only if the events {XA} and {YB} are independent for all sets A and B: 𝖯(XA,YB)=𝖯(XA)𝖯(YB) for all A, B.

  7. 7.

    An equivalent, but easier to check, condition for independence (of discrete or continuous rvs) is: FX,Y(x,y)=FX(x)FY(y). For discrete rvs, independence is also equivalent to pX,Y(x,y)=pX(x)pY(y), whereas for continuous rvs it is equivalent to fX,Y(x,y)=fX(x)fY(y). When just checking factorisation within the range where the rvs are non-zero, variational independence must also be verified.

  8. 8.

    Lack of independence can be shown using the two-point method; showing that fX,Y(x1,y1)fX,Y(x2,y2)fX,Y(x1,y2)fX,Y(x2,y1) for some x1,x2,y1,y2. Alternatively, show that fX|Y(x|y)fX(x) for some y.