Home page for accesible maths 5.7 Conditional Distributions

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5.8 Key definitions and Relationships

Let (X,Y) be a bivariate rv.

  1. 1.

    The joint cdf is FX,Y⁢(x,y)=𝖯⁡(X≤x,Y≤y). FX⁢(x)=FX,Y⁢(x,∞).

  2. 2.

    For a discrete rv, the joint pmf is pX,Y⁢(x,y)=𝖯⁡(X=x,Y=y).

  3. 3.

    For a continuous rv, the joint pdf is fX,Y⁢(x,y)=∂2∂⁡x⁢∂⁡y⁢FX,Y⁢(x,y).

  4. 4.

    For discrete rvs X and Y, the marginal pmf of X, is pX⁢(x)=∑j=-∞∞pX,Y⁢(x,j), and the conditional pmf of X given Y=y is pX|Y(x|y)=pX,Y(x,y)/pY(y).

  5. 5.

    For continuous rvs X and Y, the marginal pdf of X is fX⁢(x)=∫t=-∞∞fX,Y⁢(x,t)⁢dt, and the conditional pdf of X given Y=y is fX|Y(x|y)=fX,Y(x,y)/fY(y).

  6. 6.

    X and Y are independent if and only if the events {X∈A} and {Y∈B} are independent for all sets A and B: 𝖯⁡(X∈A,Y∈B)=𝖯⁡(X∈A)⁢𝖯⁡(Y∈B) for all A, B.

  7. 7.

    An equivalent, but easier to check, condition for independence (of discrete or continuous rvs) is: FX,Y⁢(x,y)=FX⁢(x)⁢FY⁢(y). For discrete rvs, independence is also equivalent to pX,Y⁢(x,y)=pX⁢(x)⁢pY⁢(y), whereas for continuous rvs it is equivalent to fX,Y⁢(x,y)=fX⁢(x)⁢fY⁢(y). When just checking factorisation within the range where the rvs are non-zero, variational independence must also be verified.

  8. 8.

    Lack of independence can be shown using the two-point method; showing that fX,Y⁢(x1,y1)⁢fX,Y⁢(x2,y2)≠fX,Y⁢(x1,y2)⁢fX,Y⁢(x2,y1) for some x1,x2,y1,y2. Alternatively, show that fX|Y(x|y)≠fX(x) for some y.