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2.3 Discrete Random Variables

Figure 2.1 (Link) shows the CDF for a particular random variable, R (a Poisson random variable with λ=2). It is horizontal, except at r{0,1,2,3,4,,}, at which point it jumps (is discontinuous).

Figure 2.1: Link, Caption: The function 𝖯(Rx) with R a discrete (Poisson(2)) random variable.

Random variables with CDFs which are horizontal except at jump points are called discrete random variables.

The probability of outcome r (r an integer) for a discrete random variable R is given by the probability mass function (pmf) defined by

pR(r)=𝖯(R=r)=FR(r)-limiFR(r-1/i).

The probability 𝖯(R=r) is, therefore, only non-zero where there are jumps. The cdf in Figure 2.1 (Link) corresponds to non-zero probabilities for r{0,1,2,3,4,,}. For r{0,1,2,3,4,,} we have 𝖯(R=r)=0.

A discrete random variable R has a countable sample space (set of possible values), often only the integers or the non-negative integers. For simplicity we will take the sample space to be the integers in the following presentation.

Discrete random variables arise in a variety of ways:

  1. 1.

    from experiments with a natural integer valued outcome (e.g. rolling a die),

  2. 2.

    from experiments with outcomes to which integer values are assigned.

To write the cdf in terms of the pmf as a function of r for any r we need the function int(r), which denotes the largest integer smaller than or equal to r, e.g. int(3.9)=3, int(2)=2, int(-1.5)=-2.

FR(r)=𝖯(Rr)=i=-int(r)pR(i). (2.1)

If p(r) is a probability mass function then

  1. 1.

    0p(r)1 for all r,

  2. 2.

    r=-p(r)=1.

Example 2.3.1.

Why are the following not valid probability mass functions? (p(r)=0 unless otherwise specified)

  1. (a)

    p(r)=15(4-r), r=1,2,3,4,5;

  2. (b)

    p(r)=r/2, r=1,2,3,4;

  3. (c)

    p(r)=r/20, r=1,2,3,4.

Solution. 

  1. (a)

    p(5)=-1/5;

  2. (b)

    p(4)=2;

  3. (c)

    p(1)+p(2)+p(3)+p(4)=1/2.

For any event A defined as a set of possible values of the random variable R, then

𝖯(A)=𝖯(RA)=iAp(i)=iAω:R(ω)=i𝖯(ω)=ω:R(ω)A𝖯(ω).

E.g. if A={i:0im} then 𝖯(A)=i=0mp(i).