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2.2 Implicitly defined functions

We have defined the graph of the function y=f(x), xI to be the set of points of the form (x,f(x)), where x ranges over the domain. Another way to write this is: {(x,y):xI,y=f(x)}. Sometimes we want to define a set which looks a bit like the graph of a function, but for which y can have more than one value for each x.

Example 2.10 The circle with centre at the origin and radius 1 is given by the equation x2+y2=1. In other words, it is the set of points C={(x,y)2:x2+y2=1}. Note that we couldn’t write y=f(x) here because for given x(-1,1) there are two values of y such that (x,y)C: (x,1-x2) and (x,-1-x2). This notation also helps us to avoid any concerns about the domain of the function 1-x2: if x2+y2=1 then necessarily -1x1.

Example 2.11 Let us look at an example we saw earlier: y=x3/2 with x0. If y=x3/2 then y2=x3. But if we sketch the set {(x,y)2:y2=x3} then we have not only (x,x3/2) but also (x,-x3/2). We will see another way to describe this example later on.

Example 2.12 A similar example to a circle is an ellipse: if a,b>0 then

{(x,y)2:x2a2+y2b2=1}

is an ellipse with centre (0,0). In fact, if a=b then this is a circle with radius a. We can describe an ellipse with centre (s,t) in a similar way: {(x,y)2:(x-s)2a2+(y-t)2b2=1}.

In general, an equation of the form F(x,y)=c does not give a function (at least not immediately and not always), but it describes a certain set of points in the plane. The implicit function theorem (which requires some more advanced maths, and is not covered in this module) tells us whether the equation F(x,y)=c actually defines an implicit function on some neighbourhood of a given point satisfying the equation.