Home page for accesible maths 4 Chapter 4 contents

Style control - access keys in brackets

Font (2 3) - + Letter spacing (4 5) - + Word spacing (6 7) - + Line spacing (8 9) - +

4.15 Example of discriminant test

Example.

Determine the nature of the stationary points of

f(x,y)=x3+y3-3x-12y+20.f(x,y)=x^{3}+y^{3}-3x-12y+20.

Solution. We find the stationary points, then use the Theorem to classify them. To start with, we calculate the partial derivatives up to second order.

We already saw in 4.3 that fx=3x2-3f_{x}=3x^{2}-3 and fy=3y2-12f_{y}=3y^{2}-12. Thus fxx= 6x,f_{xx}=\,{6x,} fxy= 0f_{xy}=\,{0} and fyy= 6y.f_{yy}=\,{6y.} It follows that the Hessian discriminant is fxxfyy-fxy2= 36xy.f_{xx}f_{yy}-f_{xy}^{2}=\,{36xy.}

In particular, ΔP\Delta_{P} is positive if xx and yy have the same sign, and is negative if they have opposite signs. Moreover, fxxf_{xx} is positive if and only if x>0x>0.