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11.1 Modified 2015 test

(The paper below is a slightly modified version of the coursework which was set in place of the end-of-module test when flooding in Lancaster caused the cancellation of the last week of lectures in December 2015)

1. Evaluate the following integrals:

i)⁢∫12(x2-1)1/2⁢d⁢x; ii)⁢∫π2πd⁢x3⁢sin⁡x-4⁢cos⁡x.\mbox{i)}\;\int_{1}^{2}(x^{2}-1)^{1/2}\,dx;\;\;\;\;\mbox{ii)}\;\int_{\pi\over 2% }^{\pi}{{dx}\over{3\sin x-4\cos x}}.

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2. Let CC be the parametrized curve given by (x⁢(t),y⁢(t))=((t-1)2⁢et,2⁢(t-1)⁢et)(x(t),y(t))=((t-1)^{2}e^{t},2(t-1)e^{t}) for t∈ℝt\in{\mathbb{R}}.

i) Find the equations of the tangent and normal lines to CC at Q=(x⁢(2),y⁢(2))Q=(x(2),y(2)).

ii) Determine the length along the curve from P=(x⁢(0),y⁢(0))P=(x(0),y(0)) to QQ.

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3. State whether each of the following statements is true or false. Briefly (i.e. in about one sentence) justify your answer.

i) The general solution of the differential equation d2⁢yd⁢x2-3⁢d⁢yd⁢x+2⁢y=0\frac{d^{2}y}{dx^{2}}-3\frac{dy}{dx}+2y=0 is y=A⁢ex+B⁢e2⁢xy=Ae^{x}+Be^{2x}.

ii) The gradient of the curve y2-x3=0y^{2}-x^{3}=0 at a point (x,y)(x,y) is 3⁢x22⁢y\frac{3x^{2}}{2y}.

iii) u⁢(t,x)=et⁢cos⁡xu(t,x)=e^{t}\cos x is a solution of the equation ∂2⁡u∂⁡t2+∂2⁡u∂⁡x2=0\frac{\partial^{2}u}{\partial t^{2}}+\frac{\partial^{2}u}{\partial x^{2}}=0.

iv) If f⁢(0)=0f(0)=0, f⁢(1)=1f(1)=1 and f⁢(2)=2f(2)=2 then Simpson’s rule gives an estimate for the integral ∫02f⁢(x)⁢d⁢x\int_{0}^{2}f(x)\,dx of 6.

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4. Find and classify the stationary points of the function f⁢(x,y)=x55+2⁢y-x⁢y2f(x,y)={{x^{5}}\over 5}+2y-xy^{2}.

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5. Solve the initial-value problem:

(1+x2)⁢d⁢yd⁢x+x⁢y=2⁢x⁢1+x2, y⁢(0)=1.(1+x^{2})\frac{dy}{dx}+xy=2x\sqrt{1+x^{2}},\;\;y(0)=1.

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Total: 50 marks.