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Question 5

5. By considering eiθ=cosθ+isinθe^{i\theta}=\cos\theta+i\sin\theta or otherwise, show that

cos5θ=116cos5θ+516cos3θ+58cosθ,\cos^{5}\theta={{1}\over{16}}\cos 5\theta+{{5}\over{16}}\cos 3\theta+{{5}\over% {8}}\cos\theta,

and deduce the indefinite integral

cos5θdθ.\int\cos^{5}\theta\,d\theta.

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